The height h(t) measured in feet of an object dropped by an astronaut on the moon can be approximated by h(t) = h0 (0 on the bottom) - 2.7t^2, where h0 is the height from which the object was dropped. About how long would it take an object to fall to the moon (h = 0) if it were dropped by an astronaut from a height of 6 feet?

asked by Anonymous

10 years ago

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1 answer

so
0 = -2.7t^2 + 6
t^2 = 6/2.7
t = √(6/2.7) or appr 1.49 seconds

answered by Reiny

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Question

The height h(t) measured in feet of an object dropped by an astronaut on the moon can be approximated by h(t) = h0 (0 on the bottom) - 2.7t^2, where h0 is the height from which the object was dropped. About how long would it take an object to fall to the moon (h = 0) if it were dropped by an astronaut from a height of 6 feet?

1 answer

so
0 = -2.7t^2 + 6
t^2 = 6/2.7
t = √(6/2.7) or appr 1.49 seconds

Ask a New Question or answer this question.

Reiny · Answer

so 0 = -2.7t^2 + 6 t^2 = 6/2.7 t = √(6/2.7) or appr 1.49 seconds