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The height above ground level in meters of missile launched vertically, is given by h(t) = -16t cubed + 100t. Find at what time is the missile 72m above ground level? (t is time in second)

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sorry. The equation of a trajectory is
h(t) = -16t^2 + 100t
so just solve
-16t^2 + 100t = 72

thanks

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