You get 15.3 WHAT? for 1 mol KC2H3O2 (98.1g)
15.3? x (0.132/98.1) = q
Then q = mass H2O x specific heat H2O x (Tfinal-Tinitial)
The heat of solution of potassium acetate in water is -15.3 ,What will be the final temperature when 0.132 is dissolved in 550 water that is initially at 25.1 ?
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