J = mass x specific heat x (Tfinal-Tinitial) = 0
99 J = mass Pb x 24.92 J/mol
Solve for mass Pb in mols.
Convert to grams. mol = g/molar mass
The heat lost or gained by a system is related to its temperature change by a property called its heat capacity. The molar heat capacity of metals at or above room temperature equals 24.92 J/K.mol. The temperature of a block of lead (MM 207.2) was raised by 13.1 degrees when 99.0 J of heat were added to it. What is the mass of the lead block? Enter your answer with three significant figures.
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