The hard disk in a laptop computer contains a small disk that rotates at a rate of 5000 rpm. If this disk has a radius of 2.3 cm, what is the centripetal acceleration of a point at the edge of the disk?_____m/s^2

Answer 1

n= 5000 rpm =83.33 rev/s
ω=2πn=2•π•83.33=523.6 rad/s.
a(centr) = ω²R=523.6²•0.023=6305.6 m/s²