amount = 100 (1/2)^(t/5730)
b)
59 = 100 (.5)^(t/5730)
.59 = .5^(t/5730)
ln .59 = (t/5730) ln (.5)
t/5730 = ln .59/ln .5 = .76121314
t = 4361.75 yrs
The half life of Carbon-14 is 5730 years.
a. find the rule of the function that gives the amount remaining from an initial quantity of 100 milligrams of carbon14 after t years.
b. the burial cloth of an egyptian mummy i sestimated to contain 59% of the carbon 14 it contained originally. how long ago was the mummy buried?
1 answer
1 answer