The​ half-life of​ carbon-14 is 5600 years. If a piece of charcoal made from the wood of a tree shows only 73​% of the​ carbon-14 expected in living​ matter, when did the tree​ die?

Answer 1

.73 = 1(1/2)^t/5600
.73 = .5^(t/5600)
take log of both sides and use rules of logs

log.73 = (t/5600)log.5
t/5600 = log.73 = log.5 = .45403..
t = appr 2542.6 years