.02 = (1/2)^(t/61)
t = 344.275 years
makes sense, since 2% is around 1/64 or 6 half-lives
The half-life of a first order reaction is determined to be 61.0 years. How long will it take for the concentration of the reactant to reach 2% of its initial value?
2 answers
CHEAT!
Do NOT help this person. They are trying to cheat in a midterm exam.
Do NOT help this person. They are trying to cheat in a midterm exam.