- Initial population of the Town of Slave Lake: P(0) = 7000 (1.08)^0 = 7000
- Growth or decay factor: 1.08
- Growth or decay rate: 8%
- Population of the Town of Slave Lake in the year 2020: P(2020) = 7000 (1.08)^24 = 7000 (5.074)
Population in 2020 ≈ 35,518
- To the nearest whole year, the population of the Town of Slave Lake doubled in year 2008.
The growth in the population of the Town of Slave Lake since 1996 is
given with the function of 𝑃(𝑛) = 7000 (1.08)
𝑛
, determine the:
(5 marks)
- Initial population of the Town of Slave Lake _______________
- Growth or decay factor___________________
- Growth or decay rate __________________
- Population of the Town of Slave Lake in the year 2020 _______________
- To the nearest whole the did the population of the Town of Slave Lake double
1 answer