We can use the formula for gravitational force:
F = G * (m1 * m2) / r^2
where F is the gravitational force, G is the gravitational constant (6.67 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two students, and r is the distance between them.
Plugging in the given values, we get:
2.30 x 10^-8 N = (6.67 x 10^-11 N*m^2/kg^2) * (45.0 kg * 55.0 kg) / r^2
Solving for r, we get:
r = sqrt((6.67 x 10^-11 N*m^2/kg^2) * (45.0 kg * 55.0 kg) / (2.30 x 10^-8 N)) = 0.63 m
Therefore, the students are sitting about 0.6 meters (or 63 centimeters) apart.
The gravitational force of attraction between two students sitting at their desks in physics class is 2.30 x 10-8 N. If one student has a mass of 45.0 kg and the other has a mass of 55.0 kg, how far apart are the students sitting? Round your answer to the nearest tenth of a meter.
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