They do not intersect at (3,4)
(3,4) does not satisfy g(x) = 2^x - 1
RS = 2^3 - 1 = 7
LS = 4, no good
(3,4) work in f(x) = -5/3x + 9
RS = -5/3(3) + 9
= 4
So it does work in the other equation.
did you mean g(x) = 2^(x-1) ??
RS = 2^2 = 4 = RS
you must have meant that!
so clearly the solution to
-5/3x + 9 = 2^(x-1) is x = 3
The graphs of f(x)=−5/3x+9 and g(x)=2^x−1 intersect at (3, 4) .
What is the solution of −5/3x+9=2^x−1 ?
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