Y = x^2 - 3x + 6.
B^2 = (-3) = 9.
4*A*C = 4*1*6 = 24.
B^2 - 4AC = 9 - 24 = -15 = The value
under the radical.
Since the value under the radical is negative, there are 2 imaginary solutions. Therefore, the graph does not touch or cross the x-axis. So there
are no x-intercepts.
When x = zero, Y = 6. Therefore, the Y-
intercept = 6: (0,6).
The graph of y=x^2-3x+6 has how many intercepts?
(the term x^2 means x squared)
2 answers
NOTE: B^2 = (-3)^2 = 9.