g(x) = (((x+2)/3)^2) - 2
Would be my answer. Am I wrong or right sir?
The graph of f(x)-x^2 is horizontally stretched by a factor of 3, and then shifted shifted to the left 2 units and down 2 units. Which equation describes the function g that results?
-g(x) = (((x-2)/3) - 2)^2
-g(x) = (3(x-2)))^2 + 2
-g(x) = (3(x+2))^2 - 2
-g(x) = ((x+2)/3)^2 - 2
-g(x) = (((x-2)/3)^2 + 2
1 answer