The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation of the graph?
Y=cos^-1 x
Y=cot^-1 x
Y=sin^-1 x
Y=tan^-1 x
2 answers
well, sin(pi/2) = csc(pi/2) = 1
The answer is going to be y=sin^-1 x. I used desmos for this