The graph of a trigonometric function oscillates between y=1 and y=-7. It reaches its maximum at x= pi and its minimum at x=3pi. which of the following could be the equation of the function?
A) f(x)=4 cos x/2-3
B) f(x)=4 sin x/2-3
C) f(x)=4 sin 2x-3
D) f(x)=8 sin x/2-3
4 answers
Just did that
B is the answer. Btw I'm taking Pre calc too so contact me by my email artnett4 at gmail dotcom
1. B (f(x)=4cos(x/2)-3)
2. B,F,G (c=-1; a=2; b=2)
3. C (H(t)=-2.4cos(0.017t))
4. A,B,E,F (y=cos^-1x; y=cot^-1x; y=sin^-1x; y=tan^-1x)
5. C (y=sin^-1x)
6. C (48.7°)
7. C (f(g(x))=sec(sinx); domain: all real numbers; range: 1 <= x <=1.85
8. C (step 3)
2. B,F,G (c=-1; a=2; b=2)
3. C (H(t)=-2.4cos(0.017t))
4. A,B,E,F (y=cos^-1x; y=cot^-1x; y=sin^-1x; y=tan^-1x)
5. C (y=sin^-1x)
6. C (48.7°)
7. C (f(g(x))=sec(sinx); domain: all real numbers; range: 1 <= x <=1.85
8. C (step 3)
Everything but the first question is correct from Random Junior's answers. Number 1 is B. f(x) = 4sin x/2 - 3
1 answer