The given series is an arithmetic sequence because the difference between consecutive terms is constant (8 in this case). We can find the sum of the terms using the arithmetic series formula:
S = (n/2)(2a + (n-1)d)
Where:
S = sum of the terms
n = number of terms
a = first term
d = common difference
In this case, a = 17, d = 8, and n = 6. Plugging these values into the formula:
S = (6/2)(2(17) + (6-1)(8))
S = (3)(34 + 5(8))
S = (3)(34 + 40)
S = (3)(74)
S = 222
Therefore, the sum of the terms of the series is 222.
The given series has six terms. What is the sum of the terms of the series?
17 + 25 + 33 + . . . + 57
1 answer
1 answer