y' is a common factor
y' (6y^2 - x) = x+y
y' = (x+y)/(6y^2 - x)
The given equation is a partial answer to a calculus problem. Solve the equation for the symbol y'.
6y2y' − y − xy' = x
y' =
1 answer
6y2y' − y − xy' = x
y' =
1 answer
1 answer
2 answers
0 answers
1 answer