Let's go through your questions one by one:
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Range of the Data in the Boxplot: The range is calculated as the difference between the maximum and minimum values represented in the boxplot. Without seeing the boxplot, I can’t provide a definitive answer. However, if the minimum value is 59 and the maximum value is 77 (as per your listed numbers), the range would be: \[ \text{Range} = 77 - 59 = 18 \]
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Statistics NOT Determined from a Boxplot: A boxplot (or box-and-whisker plot) provides a visual summary of the data including the minimum, first quartile (Q1), median (Q2), third quartile (Q3), and maximum. It does not show the mean or average. Therefore, the answer is:
- The average or mean
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Median of the Data in the Boxplot: Again, without seeing the boxplot, I can't provide a definitive answer. However, if the median value (as per your options) is distinctly identifiable from the boxplot’s marker, you would choose that value. If it is not provided, I can’t define it exactly.
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Left-Handed Students in the "6 to 10" Class: Similarly, I cannot see the two-way table you referenced. If the total number of left-handed students in "6 to 10" is provided in your options, you should select the number stated on the table.
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Finding the Median of the Given Data: To compute the median of the dataset: \[ 19, 21, 18, 17, 18, 22, 46 \] First, we sort the numbers: \[ 17, 18, 18, 19, 21, 22, 46 \] Since there are 7 numbers (an odd count), the median is the middle number, which is the fourth number in this sorted list:
- Median = 19
So, to summarize:
- The range (if max = 77 and min = 59) is 18.
- You cannot determine the average or mean from a boxplot.
- Without seeing the boxplot, I cannot provide the median.
- The answer for left-handed students in the "6 to 10" class is based on the table, which I cannot see.
- The median of the given data is 19.
1 answer