Asked by cici
The geometric and arithmetic mean of the two numbers are 8 and 17 respectively.
1. Find the bigger number.
2. Find the smaller number.
3. Find the harmonic mean.
1. Find the bigger number.
2. Find the smaller number.
3. Find the harmonic mean.
Answers
Answered by
Reiny
let the two numbers be x and y
(x+y)/2 = 17
x+y = 34 --> y = 34-x
√(xy) = 8
xy=64
x(34-x) = 64
x^2 - 34x = -64
x^2 - 34x + 289 = 289-64 ---> I completed the square
(x-17)^2 = 225
x-17 = ±15
x = 32 or x = 2
if x = 32, y = 2
if x = 2, y = 32 , (called symmetric solution)
The bigger is 32, the smaller is 2
If I recall correctly, the harmonic mean would be
2/(1/2 + 1/32)
= 2/( 17/32)
= 64/17
(x+y)/2 = 17
x+y = 34 --> y = 34-x
√(xy) = 8
xy=64
x(34-x) = 64
x^2 - 34x = -64
x^2 - 34x + 289 = 289-64 ---> I completed the square
(x-17)^2 = 225
x-17 = ±15
x = 32 or x = 2
if x = 32, y = 2
if x = 2, y = 32 , (called symmetric solution)
The bigger is 32, the smaller is 2
If I recall correctly, the harmonic mean would be
2/(1/2 + 1/32)
= 2/( 17/32)
= 64/17
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