To construct a confidence interval for the proportion of people who performed volunteer work, we use the formula for the confidence interval for a population proportion:
\[
\hat{p} \pm z \cdot \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}
\]
Step 1: Calculate \(\hat{p}\)
From the previous calculation, we have:
\[
\hat{p} = 0.397
\]
Step 2: Find the critical value \(z\) for a 99.5% confidence level
For a 99.5% confidence interval, the significance level \(\alpha\) is:
\[
\alpha = 1 - 0.995 = 0.005
\]
Since we are looking for the z-value corresponding to the upper 0.0025 tail (because we need half the alpha for a two-tailed test), we can find \(z\) using a standard normal distribution table or calculator. The critical value for \(z\) at 99.5% is approximately:
\[
z \approx 2.807
\]
Step 3: Calculate the standard error (SE)
Now, we can calculate the standard error (SE):
\[
SE = \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}} = \sqrt{\frac{0.397(1 - 0.397)}{1308}}
\]
Calculating \(1 - \hat{p}\):
\[
1 - \hat{p} = 1 - 0.397 = 0.603
\]
Now plug it into the SE formula:
\[
SE = \sqrt{\frac{0.397 \times 0.603}{1308}} \approx \sqrt{\frac{0.239991}{1308}} \approx \sqrt{0.0001834} \approx 0.01355
\]
Step 4: Calculate the margin of error (ME)
The margin of error (ME) is given by:
\[
ME = z \cdot SE \approx 2.807 \cdot 0.01355 \approx 0.0380
\]
Step 5: Construct the confidence interval
Now we can construct the confidence interval:
\[
(\hat{p} - ME, \hat{p} + ME) = (0.397 - 0.0380, 0.397 + 0.0380) = (0.359, 0.435)
\]
Final Answer
The 99.5% confidence interval for the proportion of people who performed volunteer work during the past year is:
\[
(0.359, 0.435)
\]
When rounded to three decimal places, the interval is approximately:
\[
(0.359, 0.435)
\]