the general "hang time" of a punt is measured to be 4.5sec. if the ball was kicked @ an angle of 63deg. above the horizontal & was caught @ the same level from which it was kicked, what was its initial speed?

Answer 1

time to top = 4.5/2 = 2.25 seconds
vertical velocity v = Vo + a t
at top v = 0
0 = Vo - 9.8 (time to top)
Vo = 9.8 (2.25)
Vo = 22.05
sin 63 = 22.05/speed
speed = 22.05/ .891
=24.7