To determine the bonds broken when hydrazine (N₂H₂) burns in oxygen (O₂), we first need to look at the chemical reaction for the combustion of hydrazine. The overall reaction can be simplified as:
\[ \text{N}_2\text{H}_2 + \text{O}_2 \rightarrow \text{N}_2 + \text{H}_2\text{O} \]
Next, let’s identify the bonds involved.
Reactants:
-
Hydrazine (N₂H₂):
- 1 N-N bond (between the two nitrogen atoms)
- 2 N-H bonds (between each nitrogen and hydrogen)
-
Oxygen (O₂):
- 1 O=O bond (the double bond between the two oxygen atoms)
Bonds in Reactants:
- 1 N-N bond
- 2 N-H bonds
- 1 O=O bond
Total Bonds Broken:
So, counting all the bonds broken during the reaction:
- N-N bond from N₂H₂
- 2 N-H bonds from N₂H₂
- O=O bond from O₂
Summary:
The total number of bonds broken in the combustion of hydrazine in oxygen is:
- 1 (N-N)
- 2 (N-H)
- 1 (O=O)
Total: 4 bonds broken (1 N-N, 2 N-H, 1 O=O).