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the fundamental theorem of calculus,

f(x)=∫(0,x) t^3+2t^2+2dt, and find f"(x).

my answer was:
f'(x)=x^3+x^2+2
f"(x)=x^4/4 + 2x^3/3 + 2x
it said its wrong.

1 answer

well, yeah.

f'' = 3x^2 + 2x

why did you take the antiderivative to go from f' to f''?

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