Let's tackle the problem step by step.
Part A: Fill out the table
The function is given as \( f(t) = 3(2)^t \). We can calculate \( f(t) \) for the specified values of \( t \):
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When \( t = 0 \): \[ f(0) = 3(2)^0 = 3(1) = 3 \]
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When \( t = 2 \): \[ f(2) = 3(2)^2 = 3(4) = 12 \]
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When \( t = 5 \): \[ f(5) = 3(2)^5 = 3(32) = 96 \]
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When \( t = 7 \): \[ f(7) = 3(2)^7 = 3(128) = 384 \]
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When \( t = 10 \): \[ f(10) = 3(2)^{10} = 3(1024) = 3072 \]
Now filling out the table:
| t | f(t) | |-----|--------| | 0 | 3 | | 2 | 12 | | 5 | 96 | | 7 | 384 | | 10 | 3072 |
Part B: The y-intercept
The y-intercept occurs when \( t = 0 \). From our calculations:
- The y-intercept is \( (0, f(0)) = (0, 3) \).
Part C: The domain of the function
Given the context that \( t \) represents time in hours since the pumpkin patch opened, the domain consists of non-negative hours. Therefore, we can express the domain as:
- \( t \geq 0 \).
Thus, the answer to Part C is \( t > -1 \) because technically the function is defined for all \( t \geq 0 \) but if we want to indicate that \( t \) can approach 0, we can say \( t > -1 \).
Complete Summary of Answers:
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Part A:
- Table filled.
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Part B:
- The y-intercept is \( (0, 3) \).
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Part C:
- The domain is \( t \geq 0 \) (or \( t > -1 \)).