The function y = x^2 + 2 undergoes a reflection. Which of the following could NOT represent f' (x), the image of f after the reflection?

a. y = x^2 - 4x + 5
b. y = x^2
c.160
d. y = -x^2

1 answer

To determine which option could NOT represent \( f'(x) \), the image of \( f(x) = x^2 + 2 \) after a reflection, we need to consider the properties of reflection and the form of the original function.

  1. Reflection across the x-axis: This changes \( f(x) \) to \( -f(x) \). For the given function, this would be: \[ -f(x) = -(x^2 + 2) = -x^2 - 2. \]

  2. Reflection across the y-axis: This changes \( f(x) \) to \( f(-x) \). For the original function: \[ f(-x) = (-x)^2 + 2 = x^2 + 2, \] which is the same as the original function.

  3. Other types of reflections: These involve combinations of transformations, but we'll primarily focus on the following potential transformations that are related to the given options.

Now, let's analyze each option:

  • Option a: \( y = x^2 - 4x + 5 \) can be rewritten in vertex form. This is a translation and does not represent a simple reflection of \( f(x) \).

  • Option b: \( y = x^2 \) represents a reflection across the horizontal axis followed by shifting down, and would still reflect the general parabola structure of the original function.

  • Option c: \( 160 \) is a horizontal line. A simple constant function does not represent the reflection of a quadratic function such as \( f(x) \).

  • Option d: \( y = -x^2 \) would represent a reflection of \( f(x) \) across the x-axis for the whole function, yielding a function that opens downward.

Conclusion: The option that could NOT represent \( f'(x) \), the image of \( f \) after reflection, is:

c. 160 (a constant function does not reflect a quadratic form).