Let's analyze the function \( y = -6x \).
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Graph Behavior: The function is a linear function because it is in the form \( y = mx + b \), where \( m = -6 \) and \( b = 0 \). Thus, the graph forms a straight line.
True Statement:
- B. The graph forms a straight line.
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Quadrant Analysis:
- When \( x > 0 \): \[ y = -6x < 0 \quad \Rightarrow \quad \text{Graph is below the x-axis, which means it's in the fourth quadrant.} \]
- When \( x < 0 \): \[ y = -6x > 0 \quad \Rightarrow \quad \text{Graph is above the x-axis, which means it's in the second quadrant.} \]
True Statements:
- E. When x is greater than 0, the graph is entirely in the fourth quadrant.
- F. When x is less than 0, the graph is entirely in the second quadrant.
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Regarding Quadrants:
- C. is false because when \( x > 0 \), the graph does not lie in the first quadrant.
- D. is false because when \( x < 0 \), the graph is not in the third quadrant; it is actually in the second quadrant.
Summary of the true statements:
- B. The graph forms a straight line.
- E. When x is greater than 0, the graph is entirely in the fourth quadrant.
- F. When x is less than 0, the graph is entirely in the second quadrant.