The function L = 0.8T2 models the relationship between L, the length in feet of a pendulum, and T, the period in seconds of the pendulum. Which value is closest to the period in seconds for a pendulum that is 30 feet long?
answer choices
5.4 seconds
4.9 seconds
6.8 seconds
6.1 seconds
3 answers
5.4 seconds
Why is the answer 6.1
To find the period for a pendulum that is 30 feet long, you need to substitute L = 30 into the equation L = 0.8T^2 and solve for T.
30 = 0.8T^2
30 / 0.8 = T^2
37.5 = T^2
T = sqrt(37.5)
T ≈ 6.1237 seconds
So the closest value to the period in seconds for a pendulum that is 30 feet long is 6.1 seconds, rounded to the nearest tenth.
30 = 0.8T^2
30 / 0.8 = T^2
37.5 = T^2
T = sqrt(37.5)
T ≈ 6.1237 seconds
So the closest value to the period in seconds for a pendulum that is 30 feet long is 6.1 seconds, rounded to the nearest tenth.
1 answer