the function has a real zero in the given interval. approximate this solution correct to two decimal places: f(x)=x^4-x^3-7x^2+5x+10; (2,3)

Answer 1

y =x^4-x^3-7x^2+5x+10
y' = 4x^3 -3x^2 -14x +5
start with x1 = 2.5
calculate y there call it y1
calculate y' there, call it m
next guess at x2 = x1 - y/m

Answer 2

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