A. V = Vo + g*Tr = 0, Tr = -Vo/g = Rise time.
T1 = Tr + Tf = Time to rise from launching point(90Ft.) to max ht. and return to launching point. Tr = Tf; Therefore, T1 = 2Tr = -2Vo/g.
Vo*T2 - 16T2^2 = 90, 50T2-16*50^2 = 90, 50T2-40,000 = 90,
50T2 = 40,090, T2 = 802 Seconds To fall 90 Ft. to gnd.
T = T1+T2, T = -2Vo/g + 802 = Time to rise to max ht. and fall to gnd.
T = (-100/-32) + 802 = 805 Seconds.
B. V^2 = Vo^2 + 2g*h = 0, h = -Vo^2/2g, Vo = 50 Ft/s, g = -32 Ft/s^2, h = ?.
The function H(t) = -16t2 + vt + s shows the height H (t), in feet, of a projectile launched vertically from s feet above the ground after t seconds. The initial speed of the projectile is v feet per second.
Part A: The projectile was launched from a height of 90 feet with an initial velocity of 50 feet per second. Create an equation to find the time taken by the projectile to fall on the ground. (2 points)
Part B: What is the maximum height that the projectile will reach? Show your work. (2 points)
Part C: Another object moves in the air along the path of g(t) = 28 + 48.8t where g(t) is the height, in feet, of the object from the ground at time t seconds.
Use a table to find the approximate solution to the equation H(t) = g(t), and explain what the solution represents in the context of the problem? [Use the function H(t) obtained in Part A, and estimate using integer values] (4 points)
Part D: Do H(t) and g(t) intersect when the projectile is going up or down, and how do you know?
1 answer
1 answer