You have to take f(x/2), not f(x). Thus, the derivative is
1/2 e^(-(x/2)^2) = 1/2 e^(-x^2/4)
So, at x=1, the slope is 1/2 e^(-1/4) = 0.3894
So, it looks like (b) is the choice. See the graphs here:
http://www.wolframalpha.com/input/?i=plot+y%3D%E2%88%9A%CF%80%2F2+*+erf%28x%2F2%29%2C+y%3D0.3894%28x-1%29+%2B0.461
The function g is given by the formula
g(x)= ∫[0,x/2] e^(-t^2)dt. An equation for the tangent line to the graph of g at the point x=1 is
a) y-0.461=0.779(x-1)
b) y-0.461=0.389(x-1)
c) y-0.461=1.558(x-1)
d) y-0.461=0.184(x-1)
e) y-0.461=0.368(x-1)
I took the derivative and got e^(-x^2)*(1/2 ) in order to find the slope and then plugged in 1 but i am keep getting 0.184 which is wrong. Please help
1 answer