Asked by smarty pants
The function f(x)=x2−1
is reflected over the y-axis. Choose the equation that correctly identifies g(x)
.(1 point)
Responses
g(x)=x2+1
g left parenthesis x right parenthesis equals x squared plus 1
g(x)=−x2−2
g left parenthesis x right parenthesis equals negative x squared minus 2
g(x)=−x2+1
g left parenthesis x right parenthesis equals negative x squared plus 1
g(x)=x2−1
is reflected over the y-axis. Choose the equation that correctly identifies g(x)
.(1 point)
Responses
g(x)=x2+1
g left parenthesis x right parenthesis equals x squared plus 1
g(x)=−x2−2
g left parenthesis x right parenthesis equals negative x squared minus 2
g(x)=−x2+1
g left parenthesis x right parenthesis equals negative x squared plus 1
g(x)=x2−1
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To reflect the function \( f(x) = x^2 - 1 \) over the y-axis, we need to replace \( x \) with \( -x \).
When we do that, we get:
\[
g(x) = f(-x) = (-x)^2 - 1 = x^2 - 1
\]
So, the reflection of \( f(x) \) over the y-axis gives us:
\[
g(x) = x^2 - 1
\]
Therefore, the correct equation for \( g(x) \) is:
\[
g(x) = x^2 - 1
\]
From the provided options, the correct choice is:
**g(x) = x² - 1**.
When we do that, we get:
\[
g(x) = f(-x) = (-x)^2 - 1 = x^2 - 1
\]
So, the reflection of \( f(x) \) over the y-axis gives us:
\[
g(x) = x^2 - 1
\]
Therefore, the correct equation for \( g(x) \) is:
\[
g(x) = x^2 - 1
\]
From the provided options, the correct choice is:
**g(x) = x² - 1**.
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