The function defined below satisfies Rolle's Theorem on the given interval. Find the value of c in the interval (-3, -2) where f'(c)=0.
f(x) = x + 6x-1 , [-3, -2]
Round your answer to two decimal places.
4 answers
I dislike f(x). It is linear, so cannot satisfy the theorem.
maybe x^2 + 6 x - 1 ?
I thought of that, but in that case, f(-3) ≠ f(-2), so the theorem does not apply.
i think its x+6x^-1