To find the number of bacteria after 5 hours, we can substitute t = 5 into the function B(t) = 300(2)t.
B(5) = 300(2)^5
B(5) = 300 * 32
B(5) = 9600
Therefore, there are 9600 bacteria after 5 hours.
The function B(t) = 300(2)t
gives the number of bacteria after t
hours. How many bacteria exist after 5 hours? (1 point)
Responses
9600
9600
7.776 ×10^13
7.776 ×10^
13
3000
3000
t= 5
1 answer