To find the number of bacteria after 5 hours, we can substitute t = 5 into the function B(t).
B(5) = 300(2)5
B(5) = 300(2^5)
B(5) = 300 * 32
B(5) = 9600
Therefore, there are 9600 bacteria after 5 hours.
The function B(t) = 300(2)t
gives the number of bacteria after t
hours. How many bacteria exist after 5 hours? (1 point)
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1 answer