Question

The function A = s^2 giving the area of a square as a function of its side length
whats the
Linear or Nonlinear:


Domain:


Range:


Increasing or Decreasing:


End behavior:

Answer 1

end behavior write diffrent just numbers

Answer 2

The function \( A = s^2 \) represents the area \( A \) of a square as a function of its side length \( s \). Let's analyze the function in terms of the specified criteria:

1. **Linear or Nonlinear**:
- The function is **Nonlinear** because it is a quadratic function (the variable \( s \) is squared).

2. **Domain**:
- The domain of the function is \( s \geq 0 \). In practical terms, the side length of a square cannot be negative, so the domain in interval notation is \( [0, \infty) \).

3. **Range**:
- The range of the function is \( A \geq 0 \). Since the area is always non-negative, the range in interval notation is \( [0, \infty) \).

4. **Increasing or Decreasing**:
- The function \( A = s^2 \) is **increasing** for \( s \geq 0 \) because as the side length \( s \) increases, the area \( A \) also increases.

5. **End Behavior**:
- As \( s \) approaches infinity (\( s \to \infty \)), \( A \) also approaches infinity (\( A \to \infty \)). As \( s \) approaches 0 (\( s \to 0 \)), \( A \) approaches 0 (\( A \to 0 \)). Therefore, the end behavior can be summarized as:
- \( \lim_{s \to 0} A(s) = 0 \)
- \( \lim_{s \to \infty} A(s) = \infty \)

To summarize:

- **Linear or Nonlinear**: Nonlinear
- **Domain**: \( [0, \infty) \)
- **Range**: \( [0, \infty) \)
- **Increasing or Decreasing**: Increasing
- **End Behavior**:
- \( \lim_{s \to 0} A(s) = 0 \)
- \( \lim_{s \to \infty} A(s) = \infty \)

Answer 3

Sure! Here’s the end behavior represented with just numbers:

- **End Behavior**:
- As \( s \to 0 \), \( A \to 0 \)
- As \( s \to \infty \), \( A \to \infty \)

In numerical format:

- \( (0, 0) \) and \( (\infty, \infty) \)