The fuel cell of h2 + o2 --> 2h2o has a cell potential of 1.23 V... If The equation for Ecell = Cathode - Anode, why wouldn't the cell be -.43 because anode = oxidation and cathode = reduction, right?

Similar Questions
  1. The following galvanic cell at standard conditions has a potential of 0.03 V:Ag+(aq) + Fe2+(aq) → Fe3+(aq) + Ag(s). What would
    1. answers icon 3 answers
  2. Cell Potential at EquilibriumFor a single galvanic cell based on the (unbalanced) reaction: Ag+(aq) + Zn(s) = Zn2+(aq) + Ag(s)
    1. answers icon 3 answers
    1. answers icon 2 answers
    1. answers icon 3 answers
more similar questions