The fringe width at a distance of 50cm from the slits in Yong's experiment for light of wavelength 6000Angstrom is 0.048cm.find the fringe wide at the same distance for wavelength=5000Angstrom?

Answer 1

We can use the formula for fringe width:

w = λD / d

where w is the fringe width, λ is the wavelength of light, D is the distance from the slits to the screen, and d is the distance between the slits.

We are given that D = 50 cm, λ1 = 6000 Å, w1 = 0.048 cm, and we want to find λ2 and w2.

First, we can solve for d using the given values:

w1 = λ1D / d
d = λ1D / w1
d = (6000 Å) (50 cm) / (0.048 cm)
d ≈ 6.25 x 10^6 Å

Now we can plug in the values for λ2 and solve for w2:

w2 = λ2D / d
w2 = (5000 Å) (50 cm) / (6.25 x 10^6 Å)
w2 ≈ 0.04 cm

Therefore, the fringe width at a distance of 50 cm from the slits for light of wavelength 5000 Å is approximately 0.04 cm.