The frequency of oscillations of a pendulum varies inversely as the square root of the length of the pendulum. If a pendulum of length 25 feet oscillates with a frequency of 100 swings per minute, what would be the frequency of a pendulum of length 16 feet?

Answer 1

f = k(1/√l)
given: when l = 25 when f = 100
100 = k(1/√100) ----> k = 1000

so f = 1000(1/√l)

plug in l = 16 to find f

Answer 2

What is L?