ln(k2/k1) = A*Ea*(1/T1 - /T2)/RT
Substitute and solve for k2. Remember to convert kJ to J.
the frequency factor and activation energy for a chemical reaction ate A=4.8 x 10^-12cm^3 and Ea=11.1kJ/mol at 327 K respectively. Determine the rate constant for this reaction at 327K
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