The freezing point of ethanol is -114.6 deg Celsius and its Kf value is 2.00degC/m. What is the freezing point for a solution prepared by dissolving 50.0g of glycerin in 200g ethanol?

Question

I thought it may have been using the formula deltaT=Kf*m, but I'm not sure.

Answer 1

You have it right.
dT = 2.00*m

You need m. That is
m = mols/kg solvent and you can get mols by mol = grams/molar mass

After you have dT then subtract from normal freezing point to obtain new freezing point.