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The fourth term of an AP is 8 and the sum of the first ten terms is 40. Find the first term and the tenth term.

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T4 = a+3d = 8
S10 = 5(2a+9d) = 40

a = 16
d = -8/3

T1 = 16
T10 = 16 + 9(-8/3) = -8

check, sequence is

16 40/3 32/3 8 16/3 8/3 0 -8/3 -16/3 -8 ...

Sum of 1st 10 terms = 40

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