fourth term is 11 ---> a+3d = 11
sixth term is 17 ----> a+5d = 17
subtract them
2d = 6
d = 3
back in a+3d = 11
a + 9 = 11
a = 2
tenth term = a+9d = 2+9(3) = 29
the forth term of an A.P is 11 and the sixth term is 17 find the tenth term?
2 answers
a+9d =2+9(3)=29