The formula unit for copper(I) sulfide is composed of 2 Cu\(^+\) ions and 1 S\(^2-\) ion.
This is because copper(I) means that copper has a +1 oxidation state, while sulfur in sulfide has a -2 oxidation state. To balance the charge, two Cu\(^+\) ions (totaling +2) pair with one S\(^2-\) ion (totaling -2).
Therefore, the correct option is:
- 2 Cu\(^+\) ions and 1 S\(^2-\) ion.