The key features of the function \( t = h\sqrt{4} \) can be analyzed as follows:
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Increasing Function: The function is indeed an increasing function. Since \( \sqrt{4} = 2 \), the formula simplifies to \( t = 2h \). As the height \( h \) increases, the time \( t \) also increases linearly, which means it increases at a constant rate rather than not at a constant rate.
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Minimum Point: The minimum point of the function is at \( (0, 0) \). This indicates that when the height \( h \) is 0 feet, the time \( t \) it takes for the object to fall to the ground is also 0 seconds, not 100 seconds.
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Domain: The domain of this function is \( h \geq 0 \), not \( h \leq 0 \). This means that only positive heights (including zero) are being studied, as negative heights do not have physical relevance in this context.
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Rate of Increase: The function \( t = 2h \) shows a linear relationship between height and time. Thus, the time it takes for an object to fall increases at a constant rate of 2 seconds per foot of height.
So, only the first statement captures some degree of the increasing behavior, even though it mentions that it does not increase at a constant rate, which is incorrect in this context as it does increase at a constant rate. None of the other statements accurately describe the function based on the features mentioned.
To summarize:
- The correct interpretation would be that the function is linear and increasing at a constant rate, with \( t \) being 0 when \( h = 0 \), and the domain should be \( h \geq 0 \).