v=4.5m/s
a=0.4m/s
t=12s
d= vt+1/2at^2
d= 4.5(12) + 1/2(0.4)(12)^2
d= 54+28.8
d= 82.8m
The formula below can be used to find the distance (d) traveled by an object, where v represents the initial velocity of the object, t represents the time, in seconds, and d represents the acceleration, in meters per second squared.
d=vt+1/2at with a a square route of 2
A bicycle traveling at a velocity of 4.5 meters per second accelerates down a hill at a constant rate of 0.4 meters per second squared for 12 seconds. What is the distance, in meters, that the bicycle travels?
1 answer