At 37.0ºC the heat of vaporization Lv for water is 2430 kJ/kg or 580 kcal/kg.
Heat of Fusion and vaporization at 0℃ for water(ice) L(f)= 334 kJ/kg.
m(cond) •L(v)=ML(f)
M= m(cond) •L(v)/ L(f)=
=7.4•10⁻³•2430000/334000 =5.38•10⁻² kg = =53.8 g
The formation of condensation on a glass of ice water causes the ice to melt faster than it would otherwise. If 7.40 g of condensation forms on a glass containing water and 210 g of ice, how many grams will melt as a result? Assume no other heat transfer occurs. Use the heat of vaporization of water at 37°, as an approximation, in this problem.
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