The force that friction exerts on a car is proportional to its mass. Suppose friction exerts 6272

Question

newtons

of force on a 1600

kilogram

car on a wet road. How many newtons of force would friction exert on a 2400kg

car under the same conditions?

Answer 1

Let F be the force of friction on the 1600kg car and m be its mass.

The force of friction is proportional to the mass, so we can set up the proportion:

F/1600 = 6272/2400

Now we can solve for F:

F = (6272/2400) * 1600
F = 4.16 * 1600
F = 6656

Therefore, friction would exert 6656 newtons of force on a 2400kg car under the same conditions.