The force on a charge moving in a magnetic field is given by the equation F = qvBsinθ, where F is the force, q is the charge, v is the velocity, B is the magnetic field strength, and θ is the angle between the velocity vector and the magnetic field vector.
To find the angle at which the force is half of the maximum force, we can set F = (1/2)F_max and solve for θ.
(1/2)F_max = qvBsinθ
Since sinθ has a maximum value of 1, we can rewrite the equation as:
(1/2)F_max = qvB
Now we can solve for θ.
(1/2)F_max = qvB
(1/2)(qvB) = qvB
(1/2) = sinθ
sinθ = 1/2
θ = sin^(-1)(1/2)
θ = 30°
Therefore, the angle between the velocity vector and the magnetic field vector when the force is half of the maximum force is 30°.
Answer: D. 30°
The force on a charge moving
with a velocity v in a magnetic
field B is half of the maximum
force when the angle between
wave B is:
A. 0°
B. 90°
C. 45°
D. 30°
1 answer