The foot F of a vertical tower FT is 7m from a point on a bearing of N58E.A man walks 12m on a bearing of 288 and sees, the top T of the tower at an angle of elevation of 45.Find the height of the tower and the distance of the man from its foot.

Answer 1

assuming the man walked from "the point", then if the man ends up at point M, we have
MF^2 = 12^2 + 7^2 - 2*7*12*cos(130°)
MF = 17.35
That means the height of the tower is also 17.35 m