The following unbalanced equation describes the reaction that can occur when (II) sulfide reacts with oxygen gas to produce lead (Il) oxide and sulfur dioxide gas: PbS+O2---> PbO + SO2 Balance the equation and describe in words the electron transfers that takes place.

Answer 1

Pb goes from +2 on the left to +2 on the right; no change.
O2 on the left goes to O on PbO with -2 and to SO2 at -2 EACH.